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...So, x cannot be 1 and our domain for this function is R/{1}. When we solve y=(2x+1)/(x-1) for x: x=(y+1)/(y-2). If y-2=0 then y=2 and x=3/0. This value is not defined on set of real numbers, R. So, y cannot be 2 and our range for this function is R/{2}. Since trigonometry has wide application ...

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