


Solve by Factoring: Why does it work?Examine the equation below: ab = 0 If you let a = 3, then logivally b must equal 0. Similarly, if you let b = 10, then a must equal 0. Now try letting a be some other nonzero number. You should observe that as long as a does not equal 0, b must be equal to zero. To state the observation more generally, "If ab = 0, then either a = 0 or b = 0." This is an important property of zero which we exploit when solving by factoring. When the example was factored into (x  2)(x  3) = 0, this property was applied to determine that either (x  2) must equal zero, or (x  3) must equal zero. Therefore, we were able to create two equations and determine two solutions from this observation. A Second Example5x^{3} = 45x Step 1Move all terms to the left side of the equation. We do this by subtracting 45x from each side. 5x^{3}  45x = 45x  45x Step 2The next step is to factor the left side completely. We first note that the two terms on the left have a greatest common factor of 5x. 5x(x^{2}  9) = 0 Now, (x^{2}  9) can be factored as a difference between two squares. 5x(x + 3)(x  3) = 0 We are left with three factors: 5x, (x + 3), and (x  3). As explained in the "Why does it work?" section, at least one of the three factors must be equal to zero. Step 3Create three subproblems by setting each factor equal to zero. 1. 5x = 0 Solving the first equation gives x = 0. Solving the second equation gives x = 3. And solving the third equation gives x= 3. Step 4The final solution is formed from the solutions to the three subproblems. x = 3, 0, 3 Visit the next page for another example. 

