Two Integers


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Posted by markmorse@nocharge.com (66.109.201.68) on October 08, 2003 at 20:07:13:

In Reply to: Problem solving question posted by on October 08, 2003 at 17:51:37:


We are asked to find two numbers, so let's assign variables to represent them.

x = first integer

y = second integer

Now we can write two equations from the given information. The difference between the two integers is -11:

x - y = -11

The sum is -3:

x + y = -3

To solve this system of two equations, we can solve one of the equations for x and then substitute the result for x in the second equation. Doing this will give us an equation that contains only y. Then we can solve it for y.

Let's solve the first equation for x by adding y to both sides:

x - y = -11

x - y + y = -11 + y

x = y - 11

Now that we know x equals y - 11, we make this substitution in the second equation. Then we solve for y:

x + y = -3

y - 11 + y = -3

2y - 11 = -3

2y = 8

y = 4

Since x = y - 11, we can find x by substituting 4 for y:

x = 4 - 11

x = -7

The two integers are -7 and 4. Does this check out?

Their difference is -11:

-7 - 4 = -11

Their sum is -3:

-7 + 4 = -3

It checks.

If you need more help with this problem, please explain what part(s) you don't understand.

~ Mark



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