Posted by intooder@yahoo.com (192.112.251.48) on October 09, 2003 at 14:55:00:
In Reply to: help posted by on October 09, 2003 at 10:05:07:
If x is any integer, odd integers can be represented as:
......(2x-3), (2x-1), (2x+1), (2x+3), (2x+5)......
Let's choose our consecutive odd numbers to be:
(2x-3), (2x-1), and (2x+1) ..... (actually you can choose any 3 from the series, this will change the value of x but the end result (the consecutive odd integers) will come out to be the same)
As per the statement of the problem:
(2x-3) + (2x-1) + (2x+1) = 5(2x +1)
Solving gives:
6x - 3 = 10x + 5
4x = -8
x = -2
Substituting the values for x in our 3 odd numbers we get:
(2(-2)- 3), (2(-2) - 1), and (2(-2) + 1)
(-7), (-5), and (-3)
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